Essay Zone.com - Free essays!
REGISTER NOW!
Login to an existing account
     
GCSE essays
A Level essays
University essays
Forum
Why join?
Essay quality
FAQ

Search forums
About us
Contact us

 

 
Centripetal force Free essay! Download now

Home > A Level > Physics > Centripetal force

Centripetal force

You can download this essay for free. All you need to do is register and submit at least one of your essays to us.

Or you can purchase this essay for just $2 instantly without registering

Downloads to date: N/A | Words: 438 | Submitted: 07-Apr-2011
Spelling accuracy: 98.2% | Number of pages: 2 | Filetype: Word .doc


This is what the first 2 pages of the essay look like

Centripetal force essay previewCentripetal force essay preview

Description

Centripetal force

Preview

Title: Centripetal force

Objective
To measure the centripetal force for whirling a mass round a horizontal circle and compare the result with the theoretical value F= m?r.

Apparatus
Rubber, glass tube about 15 cm long , weights 0.6 kg, 1.5 m of cotton string, meter rule, stop-watch, triple beam balance

Theory
When a mass m attached to a string is whirled round a horizontal circle of radius r, the centripetal force for maintaining the centripetal force for maintain the circular motion is given by F= m?r, where ? is the angular velocity of the circular motion. This force is provided by the tension of the string. The formula can also be as expressed in terms of the velocity v of the mass, where ?=v / r.
Substituting ?=v / r into the formula for F,
F= m v/r
However, the string was not horizontal as the rubber bung moved around. In fact, the bung moves in circle of radius r = L sin ? (Fig. A6.3). the tension T thus provides both the centripetal force and a force to support the weight of the bung. But resolving T into its horizontal and vertical components, show that T = m?L regardless the angle ?.
The tension T in the string is provided by the weight of screw nuts (Mg). Therefore
T = Mg
As there is no vertical motion, the vertical component of tension (T) is balanced by the weight of the rubber bung (mg):
T cos?= mg (1)
The horizontal component of the tension provides the net centripetal forces:
T sin?= m?r (2)
Substituting r = L sin? into equation (2), we can find the tension(T) in the string:
T sin?= m?( L sin?)
T = m?L

Method
1. One end of a string (~1.5 m ) was attached to a rubber bung. A length of say 0.6m of the string from the rubber bung to the glass tube was measured. This length l of the string was marked with the color pen. The free end was passed through a glass tube and then it was attached to some weights (~ 10 times the mass the ...

Download this essay in full now!

Just upload at one of your essays to our database and instantly download your selection! Registration takes seconds

Or you can download this essay for $2 immediately without registering


Comments and reviews

Reviews are written by members who have downloaded the essay

No comments yet. If you download the essay you can review it afterwards.